DC5 Type S Weight Reduction

[didz]

yes because simple physics. Less wheelspin because more power required to spin both wheels at once instead of one.

[Tofu]

^ i've been reading your post over and over again and i still don't think i understand what you're saying?

[didz]

^ i've been reading your post over and over again and i still don't think i understand what you're saying?

Ok. The traction works like this.

It takes less power to lose traction on a single spinner (no LSD) because there is only one wheel spinning in comparison to a car fitted with an LSD (both wheels spinning at the same time). How this works in giving u a better straight line time is traction; When taking off and changing gears on a car fitted with LSD, there is minimal wheel spin in comparison to a car which is not fitted with LSD.

Sorry i tend to not make sense sometimes. i hope this cleared up what i was originally trying to say.

[Tofu]

so it takes more throttle control to drive a car without lsd?

[didz]

so it takes more throttle control to drive a car without lsd?

not sure what u mean but im referring to this

they are designed for cornering but also help with straight line traction yeah?

I am saying that the only way LSD will improve straightline performance is adding traction with acceleration.

In a car which does not have an LSD, there is only ever one wheel getting the majority of the power to turn the wheel. This means that it is easy to lose traction if there is a lot of power getting put through eg: a straightline drag, you might spin your wheels a lot at the start and/or spin your wheels while changing gears.
In a car fitted with an LSD, the power is reletively distributed evenly between the two (or four) wheels. This means that in a straight line or a drag there will be less wheel spin because its more difficult for a car to spin both wheels at once rather than only spinning one.

[aaronng]

On a flat road with equal traction on left and right tyres, there will be very little benefit in a drag. It works great when one side has more traction (say the previous car on the drag strip left more rubber on the left than on the right for some reason), and then it works like how didz explained it.

[Tofu]

i think you might be getting lsd and traction control mixed up.

an LSD limits the slipage in the wheel when one of the driven wheels is not in direct contact with the ground, not adding traction to the wheel that's in contact with with the ground. if that does happen, then the car will spin out.

[qstoria]

sell type s. buy type r. then try weight redcution. in the words of jeremy clarkson

"you've bought the wrong car"

[didz]

i think you might be getting lsd and traction control mixed up.

an LSD limits the slipage in the wheel when one of the driven wheels is not in direct contact with the ground, not adding traction to the wheel that's in contact with with the ground. if that does happen, then the car will spin out.

I am not talking about traction control though. I am talking about less wheelspin because of the lsd when u launch/change gears.

[didz]

sell type s. buy type r. then try weight redcution. in the words of jeremy clarkson

"you've bought the wrong car"

thats stupid. they are both good cars and are different rides respecitvely.

[Tofu]

I am not talking about traction control though. I am talking about less wheelspin because of the lsd when u launch/change gears.

yah, so it brings back to why i ask...

so it takes more throttle control to drive a car without lsd?

[didz]

yah, so it brings back to why i ask...

in a straight line, no. in a turn possibly (not a complete expert)

The main probelm to my understanding is that once u lose traction, u really lose it lol.