What i'm about to post is a gross oversimplification: V = U + ATOriginally Posted by claymore
sydteg21 is right onAny time you get more traction and decreasing your 60 foot times you are putting more of the usable power to the ground giving more performance and that equals more speed not less. And this is in general trap speeds go up and down for many reasons.
Provided the initial velocity is the same, in this can 0, a reduction in time spent at a constant rate of acceleration will result in a lower terminal velocity...
Since a picture is worth a thousand words, here you go:
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